Respan Dataset Explorer

                            As a prompt generator for a generative AI called "Midjourney", you will create image prompts for the AI to visualize. I will give you a concept, and you will provide a detailed prompt for Midjourney AI to generate an image.
                            
                            Please adhere to the structure and formatting below, and follow these guidelines:
                            
                            Do not use the words "description" or ":" in any form.
                            Do not place a comma between [ar] and [v].
                            Write each prompt in one line without using return.
                            Structure:
                            [1] = 车内
                            [2] = a detailed description of [1] with specific imagery details.
                            [3] = a detailed description of the scene's environment.
                            [4] = a detailed description of the compositions.
                            [5] = a detailed description of the scene's mood, feelings, and atmosphere.
                            [6] = A style (e.g. photography, painting, illustration, sculpture, artwork, paperwork, 3D, etc.) for [1].
                            [7] =  a detailed description of the scene's mood, feelings, and atmosphere.
                            [ar] = Use "--ar 16:9" for horizontal images, "--ar 9:16" for vertical images, or "--ar 1:1" for square images.
                            [v] = Use "--niji" for Japanese art style, or "--v 5" for other styles.
                            
                            
                            Formatting:
                            Follow this prompt structure: "/imagine prompt: [1], [2], [3], [4], [5], [6], [7], [ar] [v]".
                            
                            Your task: Create 4 distinct prompts for each concept [1], varying in details description, environment,compositions,atmosphere, and realization.
                            
                            Write your prompts in english.
                            Do not describe unreal concepts as "real" or "photographic".
                            Include one realistic photographic style prompt with lens type and size.
                            Separate different prompts with two new lines.
                            Example Prompts:
                            
                            /imagine prompt: cute dog, fluffy fur, wagging tail, playful expression, sitting on a grassy field, under a clear blue sky, with a colorful collar, in a natural and vibrant setting, by a lake, captured with a Nikon D750 camera, 50mm lens, shallow depth of field, composition focused on the dog's face, capturing its joyful spirit, in a style reminiscent of William Wegman's iconic dog portraits. --ar 1:1 --v 5.2
                            /imagine prompt: beautiful women in the coffee shop, elegant and sophisticated, sipping a cup of steaming coffee, natural sunlight streaming through the window, soft and warm color tones, vintage decor with cozy armchairs and wooden tables, a bookshelf filled with classic novels, delicate porcelain teacups, a hint of aromatic coffee beans in the air, captured by a Leica M10 camera, 35mm lens, capturing the essence of timeless beauty, composition focused on the woman's face and hands, reminiscent of a painting by Leonardo da Vinci. --ar 1:1 --v 5.2
                            /imagine prompt: A captivating Halo Reach landscape with a Spartan amidst a battlefield, fallen enemies around, smoke and fire in the background, emphasizing the Spartan's determination and bravery, detailed environment blending chaos and beauty, Illustration, digital art, --ar 16:9 --v 5
                                                        

/imagine prompt: car interior, sleek leather seats with intricate stitching, modern dashboard lit up with vibrant screens, a panoramic sunroof revealing a starry night sky, city lights twinkling outside the windows, composition framing the driver’s seat view, capturing a sense of speed and adventure, the atmosphere rich with anticipation and excitement, futuristic design, evoking freedom and exploration, --ar 16:9 --v 5  

/imagine prompt: car interior, vintage wooden dashboard adorned with brass accents, plush seats in deep burgundy, a cozy ambiance illuminated by a warm, golden glow from filament bulbs, surrounded by a misty forest outside the fogged windows, the composition highlighting the contrast between the elegant interior and the wildness outside, feeling nostalgic and adventurous, reminiscent of classic road trips and exploration, watercolor painting style, capturing warmth and nostalgia, --ar 16:9 --v 5  

/imagine prompt: car interior, a futuristic concept with holographic displays and touch controls, minimalist design with a spacious feel, the environment outside showcasing a neon-lit cityscape at dusk, reflections of the colorful lights on the car's surfaces, the composition emphasizes the harmony between technology and urban life, invoking feelings of innovation and excitement, 3D render, capturing the essence of modernity and urban sophistication, --ar 16:9 --v 5  

/imagine prompt: car interior, a rustic pickup truck with worn leather seats and a retro dashboard, country music playing softly in the background, the landscape outside features rolling hills and open blue skies, a dirt road stretching into the distance, the composition focused on the steering wheel and the view ahead, evoking a sense of freedom and adventure, illustrative style, capturing the spirit of the open road and simplicity, --ar 16:9 --v 5  

Дай promt для понимания моделью Stable diffusion. promt содержит описание одежды персонажа Katarina из игры league of legends. Надо получить cosplay. Только точные promt одежды, начиная со слов she wearing

She is wearing a sleek, form-fitting black leather top with crimson accents that highlight her athletic build. The top is adorned with intricate silver buckles and straps that give it an edgy, battle-ready look. She also wears tight black leather pants that match her top, along with tall, dark boots that reach up to her knees, featuring metal embellishments. Her outfit is completed by a wide belt with a prominent silver buckle, and she carries two deadly daggers as part of her attire. Her long, vibrant red hair flows freely, adding a striking contrast to her dark ensemble.

select ret.*, q.*, marking.score teacher_score
from project_exam_student_result ret
         left join project_exam_student_making marking
                   on ret.student_exam_id = marking.student_exam_id and ret.paper_id = marking.paper_id and
                      ret.question_id = marking.question_id and ret.line_id = marking.line_id and marking.teacher_id = NULL
         join asktrue_paper.question_info q on q.question_id = ret.question_id
where 1 = 1
  and ret.student_exam_id = '505667198333898752'
  and ret.student_id = '505438259699142656'
  and ret.exam_id = '2075'
  and ret.paper_id = '836'
order by ret.question_id


这个sql查出来结果集是重复的两遍

If the result set from your query is showing duplicated rows, it's likely due to the way joins are constructed or the underlying data itself. Let's analyze the SQL query you've written and see how we can address the issue of duplicated data:

1. **Check for Duplicates in Joined Tables**: It's possible that there are duplicate records in `project_exam_student_making` or `asktrue_paper.question_info` that match your join conditions. You should verify that these tables contain unique entries for the join keys (particularly `student_exam_id`, `paper_id`, `question_id`, and `line_id`).

2. **LEFT JOIN with a NULL Check**: You mentioned a condition like `marking.teacher_id = NULL`. SQL uses `IS NULL` for null checks instead of `=`. This should be corrected to `marking.teacher_id IS NULL`.

3. **Expected Results from Joins**: If the `project_exam_student_making` table contains multiple entries for the specified `student_exam_id`, `paper_id`, `question_id`, and `line_id` with a `NULL` `teacher_id`, each of these would cause duplicated rows in the `ret` table when joined.

Here is your SQL with the correction for the NULL check:

```sql
SELECT ret.*, q.*, marking.score AS teacher_score
FROM project_exam_student_result ret
LEFT JOIN project_exam_student_making marking
    ON ret.student_exam_id = marking.student_exam_id
    AND ret.paper_id = marking.paper_id
    AND ret.question_id = marking.question_id
    AND ret.line_id = marking.line_id
    AND marking.teacher_id IS NULL
JOIN asktrue_paper.question_info q 
    ON q.question_id = ret.question_id
WHERE ret.student_exam_id = '505667198333898752'
    AND ret.student_id = '505438259699142656'
    AND ret.exam_id = '2075'
    AND ret.paper_id = '836'
ORDER BY ret.question_id;
```

### Steps to Debug Duplicate Issues:
- **Review Data**: Check the data in `project_exam_student_making` to see if there are multiple rows for each combination of `student_exam_id`, `paper_id`, `question_id`, `line_id` when `teacher_id` is `NULL`.
  
- **Test Joins Individually**: Run each join separately to see if either produces duplicate results.
  
- **Use DISTINCT**: As a temporary measure, add `DISTINCT` to your select statement to remove duplicates, but this should be used with caution as it might mask the underlying issue.

```sql
SELECT DISTINCT ret.*, q.*, marking.score AS teacher_score
FROM ...
```

- **Check Data Relationships**: Ensure that the relationships and foreign keys between these tables enforce the expected cardinality (e.g., one-to-one or many-to-one as needed).

By following these guidelines, you should be able to identify and resolve the duplication issue in your SQL query.

用中文回答我

好的，如果您的SQL查询结果集出现重复的行，可能是由于连接的方式或底层数据自身造成的。让我们分析一下您编写的SQL查询，并看看如何解决重复数据的问题：

1. **检查连接表中的重复项**：`project_exam_student_making` 或 `asktrue_paper.question_info` 中可能存在符合您的连接条件的重复记录。您应该验证这些表在连接键（尤其是 `student_exam_id`、`paper_id`、`question_id` 和 `line_id`）上是否包含唯一条目。

2. **对 NULL 的检查中使用LEFT JOIN**：您提到的条件是 `marking.teacher_id = NULL`。在SQL中，检查NULL应该用 `IS NULL` 而不是 `=`。所以，这应该改为 `marking.teacher_id IS NULL`。

3. **从连接中期望的结果**：如果 `project_exam_student_making` 表中包含多个 `student_exam_id`、`paper_id`、`question_id` 和 `line_id` 组合且 `teacher_id` 为 `NULL` 的条目，那么这些条目中的每一个在连接时都会在 `ret` 表中导致重复的行。

这是您的SQL，带有针对NULL检查的修正：

```sql
SELECT ret.*, q.*, marking.score AS teacher_score
FROM project_exam_student_result ret
LEFT JOIN project_exam_student_making marking
    ON ret.student_exam_id = marking.student_exam_id
    AND ret.paper_id = marking.paper_id
    AND ret.question_id = marking.question_id
    AND ret.line_id = marking.line_id
    AND marking.teacher_id IS NULL
JOIN asktrue_paper.question_info q 
    ON q.question_id = ret.question_id
WHERE ret.student_exam_id = '505667198333898752'
    AND ret.student_id = '505438259699142656'
    AND ret.exam_id = '2075'
    AND ret.paper_id = '836'
ORDER BY ret.question_id;
```

### 解决重复问题的步骤：
- **检查数据**：查看 `project_exam_student_making` 数据，看看对于指定的 `student_exam_id`、`paper_id`、`question_id`、`line_id` 和 `teacher_id` 为 `NULL` 的组合是否有多行。

- **分别测试连接**：分别运行每个连接，看看是否有导致重复结果。

- **使用 DISTINCT**：作为一种临时措施，可以在SELECT语句中添加 `DISTINCT` 来去除重复项，但这种方法应该谨慎使用，因为这可能掩盖底层问题。

```sql
SELECT DISTINCT ret.*, q.*, marking.score AS teacher_score
FROM ...
```

- **检查数据关系**：确保这些表之间的关系和外键能强制实现预期的基数关系（例如，一对一或多对一）。

通过这些步骤，您应该能够确定并解决SQL查询中的重复问题。

select ret.*, q.*, marking.score teacher_score
from project_exam_student_result ret
         left join project_exam_student_making marking
                   on ret.student_exam_id = marking.student_exam_id and ret.paper_id = marking.paper_id and
                      ret.question_id = marking.question_id and ret.line_id = marking.line_id and
                      marking.teacher_id = NULL
         join asktrue_paper.question_info q on q.question_id = ret.question_id
where 1 = 1
  and ret.student_exam_id = '505667198333898752'
  and ret.student_id = '505438259699142656'
  and ret.exam_id = '2075'
  and ret.paper_id = '836'
order by ret.question_id;

结果集中对应多条scoring_time的记录，我只需要最后一次时间的打分记录

要在SQL查询中获取每组数据中时间最新的记录，可以使用子查询或窗口函数（如果数据库支持）。以下是两种方法，可以帮助你获得每组中 `scoring_time` 最新的一条记录：

### 方法一：使用子查询

使用子查询获取最新的 `scoring_time`，然后将其与原始表连接。

```sql
SELECT ret.*, q.*, marking.score AS teacher_score
FROM project_exam_student_result ret
LEFT JOIN (
  SELECT student_exam_id, paper_id, question_id, line_id, MAX(scoring_time) AS max_scoring_time
  FROM project_exam_student_making
  WHERE teacher_id IS NULL
  GROUP BY student_exam_id, paper_id, question_id, line_id
) latest
ON ret.student_exam_id = latest.student_exam_id
AND ret.paper_id = latest.paper_id
AND ret.question_id = latest.question_id
AND ret.line_id = latest.line_id
LEFT JOIN project_exam_student_making marking
ON ret.student_exam_id = marking.student_exam_id
AND ret.paper_id = marking.paper_id
AND ret.question_id = marking.question_id
AND ret.line_id = marking.line_id
AND marking.scoring_time = latest.max_scoring_time
JOIN asktrue_paper.question_info q
ON q.question_id = ret.question_id
WHERE ret.student_exam_id = '505667198333898752'
AND ret.student_id = '505438259699142656'
AND ret.exam_id = '2075'
AND ret.paper_id = '836'
ORDER BY ret.question_id;
```

### 方法二：使用窗口函数（如果数据库支持，比如PostgreSQL、SQL Server）

如果您的数据库支持窗口函数，可以使用 `ROW_NUMBER()` 来挑选最新的记录。

```sql
WITH ranked_markings AS (
  SELECT *,
         ROW_NUMBER() OVER (PARTITION BY student_exam_id, paper_id, question_id, line_id 
                            ORDER BY scoring_time DESC) AS rn
  FROM project_exam_student_making
  WHERE teacher_id IS NULL
)
SELECT ret.*, q.*, marking.score AS teacher_score
FROM project_exam_student_result ret
LEFT JOIN ranked_markings AS marking
ON ret.student_exam_id = marking.student_exam_id
AND ret.paper_id = marking.paper_id
AND ret.question_id = marking.question_id
AND ret.line_id = marking.line_id
AND marking.rn = 1
JOIN asktrue_paper.question_info q
ON q.question_id = ret.question_id
WHERE ret.student_exam_id = '505667198333898752'
AND ret.student_id = '505438259699142656'
AND ret.exam_id = '2075'
AND ret.paper_id = '836'
ORDER BY ret.question_id;
```

这两种方法都可以帮助你筛选出您所需要的每组中 `scoring_time` 最新的一条打分记录。选择其中一种方法，具体取决于您的数据库系统和个人偏好。

List<ProjectExamStudentResult> list = resultMapper.selectPaperAnswerData(paramMap);

用java8的stream处理，对应的是scoringTime字段

如果你需要使用 Java 8 的 Stream API 来处理 `List<ProjectExamStudentResult>` 并获取每组数据中 `scoringTime` 最新的记录，可以按以下步骤进行操作。假设 `ProjectExamStudentResult` 类中有 `getScoringTime()` 方法来获取时间戳，并且有其他方法来获取用于分组的关键字段。

```java
import java.util.*;
import java.util.stream.Collectors;

public class Example {

    public static void main(String[] args) {
        List<ProjectExamStudentResult> list = resultMapper.selectPaperAnswerData(paramMap);

        // 使用stream根据一个或多个字段进行分组，同时获取每组中scoringTime最新的记录
        Map<String, ProjectExamStudentResult> latestResults = list.stream()
            .collect(Collectors.toMap(
                // 使用某个或一些唯一的字段组合作为键，可以根据需求调整
                result -> result.getStudentExamId() + "_" + result.getPaperId() + "_" + result.getQuestionId() + "_" + result.getLineId(),
                result -> result, // value为当前对象
                (existing, replacement) -> existing.getScoringTime().isAfter(replacement.getScoringTime()) ? existing : replacement
            ));

        // 将结果转为列表
        List<ProjectExamStudentResult> filteredList = new ArrayList<>(latestResults.values());

        // 现在filteredList包含了每组中scoringTime最新的记录
    }
}
```

### 说明：

- **分组键**：使用 `getStudentExamId()`、`getPaperId()`、`getQuestionId()` 和 `getLineId()` 的组合作为分组键。请根据您的实际情况选择合适的字段。

- **合并逻辑**：在 `Collectors.toMap()` 中的合并逻辑定义了如果遇到键冲突（即有相同分组键的多条记录），应该选择 `scoringTime` 更新的记录。

- **最终列表**：使用 `new ArrayList<>(latestResults.values())` 将最优结果转为列表。

本代码段假设您的 `ProjectExamStudentResult` 类包含方法以获取必要的字段（如 `getScoringTime()`）并且返回一个类型兼容的时间对象。如果 `scoringTime` 是其他格式，你可能需要适当的转换方法。

select *
from project_exam_student_result ret
where ret.student_exam_id = '505667198333898752'
  and ret.student_id = '505438259699142656'
  and ret.exam_id = '2075'
  and ret.paper_id = '836'
order by ret.question_id;

按照question_id去重

在 SQL 查询中，如果你希望按 `question_id` 去重并且只保留每个 `question_id` 的第一条记录，通常的方式是在不支持复杂窗口函数的数据库中采用自连接或子查询。如果你的数据库支持窗口函数（如 PostgreSQL、SQL Server、MySQL 8.0+ 等），可以使用窗口函数来解决这个问题。

### 使用窗口函数

这是一个在支持窗口函数的数据库中处理去重问题的推荐方法：

```sql
WITH ranked_results AS (
  SELECT ret.*,
         ROW_NUMBER() OVER (PARTITION BY ret.question_id ORDER BY ret.student_exam_id) AS rn
  FROM project_exam_student_result ret
  WHERE ret.student_exam_id = '505667198333898752'
    AND ret.student_id = '505438259699142656'
    AND ret.exam_id = '2075'
    AND ret.paper_id = '836'
)
SELECT *
FROM ranked_results
WHERE rn = 1
ORDER BY question_id;
```

### 方法说明

- **`ROW_NUMBER`**: 通过窗口函数 `ROW_NUMBER()` 给每组 `question_id` 标号，`ORDER BY ret.student_exam_id` 可替换为你的特定需求，比如按某个时间字段排序，以决定选取哪条作为每组的第一条记录。
  
- **`PARTITION BY`**: 根据 `question_id` 进行分区，确保 `ROW_NUMBER()` 的编号在每个 `question_id` 内独立递增。

- **选择第一条**: 通过 `WHERE rn = 1` 过滤掉编号不为1的行，从而只保留每组内的第一条记录。

### 如果不支持窗口函数

对于不支持窗口函数的数据库，可以考虑使用自连接。以下是基本步骤：

```sql
SELECT ret.*
FROM project_exam_student_result ret
JOIN (
  SELECT MIN(student_exam_id) as min_student_exam_id, question_id
  FROM project_exam_student_result
  WHERE student_exam_id = '505667198333898752'
    AND student_id = '505438259699142656'
    AND exam_id = '2075'
    AND paper_id = '836'
  GROUP BY question_id
) min_ids
ON ret.student_exam_id = min_ids.min_student_exam_id
AND ret.question_id = min_ids.question_id
ORDER BY ret.question_id;
```

- **子查询**: 找出每个 `question_id` 的最小 `student_exam_id`，这通常会得到 `question_id` 的第一条记录。

根据你的数据库系统和具体需求选择适合的方法。如果有特定的排序要求，可以在 `ORDER BY` 部分做调整。

docker swarm支持广域网节点吗

Docker Swarm 本身是用于在多主机上管理和编排容器的工具，它确实可以在广域网（WAN）环境中运行节点，但这需要特别的配置和注意，以确保安全性和性能。以下是一些在广域网环境中使用 Docker Swarm 需要考虑的事项：

1. **网络配置**：
   - 在广域网上，确保各个 Swarm 节点可以互相通信。这通常需要配置防火墙和网络路由，以允许 Swarm 使用的端口（如 2377 用于 Swarm 管理通信，7946 用于节点之间的通信，在覆盖网络中使用的端口 4789）开通。

2. **安全性**：
   - 因为广域网可能是公开或易受攻击的网络环境，务必启用并配置 TLS 来加密节点之间的通信。
   - 确保 Swarm 集群的管理权限受到了适当的限制，只允许可信的用户和节点访问。

3. **性能考虑**：
   - 跨广域网的网络延迟可能会影响 Swarm 的性能，特别是在进行大量节点通信或容器调度时。
   - 可以考虑使用靠近的节点或分布式的缓存和镜像存储来减轻一些网络和性能问题。

4. **节点发现和负载均衡**：
   - 在广域环境下，可能需要配置外部的 DNS 或使用公有云提供的负载均衡服务来处理节点的发现和请求的分发。

5. **数据一致性**：
   - 跨区域的数据一致性需要额外的规划，确保敏感的数据在跨区域传输时的安全和一致性。使用一些额外的数据管理工具或者服务可能是必要的。

如果正确配置，Docker Swarm 可以在广域网环境中有效运作。然而，出于安全和性能的考虑，这种设置通常需要更深入的规划和设置。如果您没有严格要求 Swarm 必须跨广域网操作，还可以考虑使用其他分布式编排和管理工具（如 Kubernetes），根据具体需求和环境来选择最合适的工具。

docker swarm 部署微服务时，如何确保Java镜像运行时向nacos注册宿主机的IP

在 Docker Swarm 中部署 Java 微服务并确保服务实例在启动时向 Nacos 注册时使用宿主机的 IP，而不是容器的内部 IP，这是一个常见的需求。为此，你可以使用以下几种策略：

### 配置 Java 应用程序使用宿主机 IP

1. **使用 Docker 环境变量**：
   - 在启动 Java 应用时，可以通过环境变量将宿主机的 IP 地址传递给应用，然后在应用中配置 Nacos 客户端使用这个 IP 进行注册。
   - 在 `docker-compose.yml` 或服务定义中，可以使用 Docker 提供的特殊字段 `{{ .Node.IP }}` 来引用 Swarm 中节点的 IP 地址。例如：
     ```yaml
     services:
       my-service:
         image: my-java-app:latest
         environment:
           - NACOS_SERVER_IP={{ .Node.IP }}
     ```
   然后在 Java 应用中，从环境变量中读取 `NACOS_SERVER_IP` 并配置 Nacos 客户端。

2. **修改 Nacos 客户端配置**：
   - 确保你的 Nacos 客户端配置允许设置服务实例的注册 IP，可以从环境变量或配置文件中动态读取宿主机的 IP 地址。

3. **Docker Network 配置**：
   - 使用 `host` 网络模式，使应用程序能够直接识别和使用主机的网络接口。然而，这种方法可能会导致容器失去部分网络隔离，需要根据具体场景谨慎使用。

### 获取宿主机 IP

在某些场景下，你可能需要一种更通用的方式来获取宿主机 IP：

- **脚本获取**：
  - 可以在容器启动时运行一个脚本来自动获取宿主机 IP，并设置为环境变量。脚本可以使用以下命令：
    ```bash
    HOST_IP=$(hostname -i)
    ```
  然后将 `HOST_IP` 传递给您的应用进行 Nacos 注册。

### Nacos 服务注册示例

假设你的 Java 应用使用 Spring Cloud Alibaba 的 Nacos 客户端，你可以在应用启动时通过以下配置解决问题：

```java
import com.alibaba.nacos.api.naming.pojo.Instance;
import com.alibaba.nacos.client.naming.NacosNamingService;

public class NacosRegistrationConfig {

    public static void registerToNacos() throws Exception {
        String serverAddr = System.getenv("NACOS_SERVER_ADDR");
        String hostIp = System.getenv("NACOS_SERVER_IP");
        NacosNamingService naming = new NacosNamingService(serverAddr);

        Instance instance = new Instance();
        instance.setIp(hostIp);
        instance.setPort(8080); // 应用服务端口
        naming.registerInstance("my-service", instance);
    }
}
```

### 总结

通过结合 Docker Swarm 的 IP 查询和 Nacos 客户端的注册配置，你可以确保 Java 微服务在广域网或其他需要真实 IP 的环境中正确注册服务。如果可能，对部署网络和安全性进行额外的考量以保护微服务的通信安全。

[root@iZ0jl2r1fhamcotthujf20Z TEST_asktrue-score-back]# docker stack deploy -c docker-compose.yml asktrue-score
yaml: invalid map key: map[interface {}]interface {}{".Node.IP":interface {}(nil)}

在使用 Docker Swarm 和 `docker stack deploy` 命令时，你遇到了一个 YAML 格式问题，提示与你的 `docker-compose.yml` 文件中 `{{ .Node.IP }}` 的使用有关。让我们一步步检查，并解决可能的错误：

### 错误分析

1. **YAML 格式问题**：
   - 错误信息表明 YAML 文件中的 key 使用了一个无效的语法。原因是 Docker Stack 的 `deploy` 命令不支持像 `docker service create` 那样直接解析 `{{ .Node.IP }}` 模板字符串。这种模板替换通常是命令行使用的，而不是在 YAML 文件中。

2. **Docker Stack 和 Docker Compose 的区别**：
   - Docker Stack 使用的 `docker-compose.yml` 文件中的变更，不支持像 Docker Compose 那样的复杂模板占位符。
   - `docker stack deploy` 不会解析 `.Node.IP` 这样的方式来自动注入节点信息。

### 解决方案

对于在 Docker Stack 中正确获取和使用宿主机的 IP 地址，你可以考虑以下方法：

1. **通过环境变量或者启动参数传递**：
   - 在实际运行时，通过外部脚本或 `docker-compose.yml` 的环境变量，手动传入实际 IP。
   - 然而，需要自行通过外部机制（比如脚本或启动命令），获取节点 IP 并传递至容器内。

2. **DNS 信息或服务发现**：
   - 使用服务发现或 DNS 机制在服务内部获取节点信息，而非通过 Stack 配置文件。

3. **自定义启动脚本**：
   - 编写一个容器启动脚本，该脚本在启动服务前获取宿主机的 IP 并设置到应用的配置环境中。

### 实践中可能的实现方案

Here’s how you can design a solution using a startup script:

**Dockerfile and Entry Script**

- Create an entrypoint script that will detect the node's IP and configure your service.

**Dockerfile:**

```dockerfile
FROM your-base-image

# Add entry script
COPY entrypoint.sh /entrypoint.sh
RUN chmod +x /entrypoint.sh

# Set entrypoint
ENTRYPOINT ["/entrypoint.sh"]
```

**entrypoint.sh:**

This script will execute when the container starts:

```bash
#!/bin/bash

# Get the host IP
HOST_IP=`hostname -i`

# Export as an environment variable or modify your config files
export HOST_IP

# Call the main process (replace with your app start command)
exec "$@"
```

**docker-compose.yml:**

Ensure your `docker-compose.yml` has the right configurations to call your service start:

```yaml
version: '3.8'

services:
  your-service:
    image: your-image:latest
    deploy:
      replicas: 1
    environment:
      # Possible other env variables
    command: ["your-start-command", "arg1", "arg2"]
```

这是一种常见的方案，使用启动脚本来动态配置你的微服务以识别正确的网络接口，从而在 Docker Swarm 环境中正常注册 Nacos。根据你的需求和环境设置，可以调整脚本的具体实现。