Respan Dataset Explorer

Below are the lengths (in meters) of Luiza's eight drives from the last time that she played golf.
 
\[\begin{aligned}
&213, 147, 156, 177, \\
&130, 23, 78, 184
\end{aligned}\]
Using the data, create a histogram.
\[0\]
\[1\]
\[2\]
\[3\]
\[4\]
\[5\]
\[6\]
\[0\]
\[50\]
\[100\]
\[150\]
\[200\]
\[250\]
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Report a problem

Let's create a histogram for Luiza's eight golf drive lengths:

**Drive lengths (meters):**  
213, 147, 156, 177, 130, 23, 78, 184

---

### Step 1: Define intervals (bins)

We can use intervals of size 50 meters for the range between 0 and 250:

| Interval | Range (meters) |
|----------|----------------|
| 1        | 0 – 49         |
| 2        | 50 – 99        |
| 3        | 100 – 149      |
| 4        | 150 – 199      |
| 5        | 200 – 249      |

---

### Step 2: Count the number of drives in each interval

- 0 – 49: 23 → 1 drive
- 50 – 99: 78 → 1 drive
- 100 – 149: 130, 147 → 2 drives
- 150 – 199: 156, 177, 184 → 3 drives
- 200 – 249: 213 → 1 drive

---

### Step 3: Frequency table

| Interval    | Number of drives (frequency) |
|-------------|------------------------------|
| 0 – 49      | 1                            |
| 50 – 99     | 1                            |
| 100 – 149   | 2                            |
| 150 – 199   | 3                            |
| 200 – 249   | 1                            |

---

### Step 4: Description of the histogram bars

- A bar of height 1 at 0 – 49  
- A bar of height 1 at 50 – 99  
- A bar of height 2 at 100 – 149  
- A bar of height 3 at 150 – 199  
- A bar of height 1 at 200 – 249

---

This histogram shows where the golf drives are most concentrated — mostly between 150 and 199 meters.

Problem
The following data points represent how many tunnels Gary the Groundhog dug each year.
\[\qquad18,5,13,9,6,2,10\]
Using the data, create a histogram. For this histogram, each bin excludes the left endpoint and includes the right endpoint.
\[0\]
\[1\]
\[2\]
\[3\]
\[4\]
\[5\]
\[0\]
\[4\]
\[8\]
\[12\]
\[16\]
\[20\]
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Report a problem

Let's create the histogram for Gary the Groundhog's tunnels dug each year:

---

### Given data:
18, 5, 13, 9, 6, 2, 10

---

### Step 1: Define bins with the rule:  
*Each bin excludes the left endpoint and includes the right endpoint*, example: (a, b]

Let's choose bins of size 4 from 0 to 20:

| Bin # | Interval      |
|-------|---------------|
| 1     | (0, 4]        |
| 2     | (4, 8]        |
| 3     | (8, 12]       |
| 4     | (12, 16]      |
| 5     | (16, 20]      |

---

### Step 2: Sort data into bins

- (0, 4]: Values greater than 0 and ≤ 4 → 2 → 1 value
- (4, 8]: Values > 4 and ≤ 8 → 5, 6 → 2 values
- (8, 12]: Values > 8 and ≤ 12 → 9, 10 → 2 values
- (12, 16]: Values > 12 and ≤ 16 → 13 → 1 value
- (16, 20]: Values > 16 and ≤ 20 → 18 → 1 value

---

### Step 3: Frequency table

| Interval | Frequency (number of years) |
|----------|-----------------------------|
| (0, 4]   | 1                           |
| (4, 8]   | 2                           |
| (8, 12]  | 2                           |
| (12,16]  | 1                           |
| (16,20]  | 1                           |

---

### Step 4: Histogram description

- Bar at (0,4] has height 1  
- Bar at (4,8] has height 2  
- Bar at (8,12] has height 2  
- Bar at (12,16] has height 1  
- Bar at (16,20] has height 1

---

This histogram shows how many tunnels Gary dug, grouped in intervals by year.

Problem
The following data points represent how many tunnels Gary the Groundhog dug each year.
\[\qquad18,5,13,9,6,2,10\]
Using the data, create a histogram.
\[0\]
\[1\]
\[2\]
\[3\]
\[4\]
\[5\]
\[0\]
\[4\]
\[8\]
\[12\]
\[16\]
\[20\]
Related content
Report a problem

Let's create a histogram for Gary the Groundhog's tunnel data:

---

### Data Points:
18, 5, 13, 9, 6, 2, 10

---

### Step 1: Define bins based on the number line given:

Bins range from 0 to 20, and it’s natural to use intervals of size 4:

| Bin Number | Interval     |
|------------|--------------|
| 1          | 0 to 4       |
| 2          | 4 to 8       |
| 3          | 8 to 12      |
| 4          | 12 to 16     |
| 5          | 16 to 20     |

---

### Step 2: Sort data into bins

- 0–4: Data points ≤ 4 → 2 → 1 value
- 4–8: 5, 6 → 2 values
- 8–12: 9, 10 → 2 values
- 12–16: 13 → 1 value
- 16–20: 18 → 1 value

---

### Step 3: Frequency table

| Interval | Frequency (Number of years) |
|----------|-----------------------------|
| 0–4      | 1                           |
| 4–8      | 2                           |
| 8–12     | 2                           |
| 12–16    | 1                           |
| 16–20    | 1                           |

---

### Step 4: Histogram description

- Bar height at 0–4 is 1
- Bar height at 4–8 is 2
- Bar height at 8–12 is 2
- Bar height at 12–16 is 1
- Bar height at 16–20 is 1

---

This histogram summarizes how many tunnels Gary dug each year, grouped into ranges of 4.

Problem
The following data points represent the final exam scores for each student in Salma's first period class.
\[\qquad69,93,72,83,57,84,69,92\]
Using the data, create a histogram. For this histogram, each bin excludes the left endpoint and includes the right endpoint.
\[0\]
\[1\]
\[2\]
\[3\]
\[4\]
\[5\]
\[6\]
\[7\]
\[8\]
\[0\]
\[20\]
\[40\]
\[60\]
\[80\]
\[100\]
Related content
Report a problem


Bonus question

Let's create a histogram for Salma's class exam scores following these guidelines:

---

### Data points (Final exam scores):  
69, 93, 72, 83, 57, 84, 69, 92

---

### Bin rule:  
*Each bin excludes the left endpoint and includes the right endpoint.*  
For example, bin (a, b] includes values greater than a and less than or equal to b.

---

### Step 1: Define intervals (bins) from 0 to 100 in increments of 20:

| Bin # | Interval      |
|-------|---------------|
| 1     | (0, 20]       |
| 2     | (20, 40]      |
| 3     | (40, 60]      |
| 4     | (60, 80]      |
| 5     | (80, 100]     |

---

### Step 2: Sort scores into bins:

- (0, 20]: none
- (20, 40]: none
- (40, 60]: 57 → 1 student
- (60, 80]: 69, 69, 72 → 3 students
- (80, 100]: 83, 84, 92, 93 → 4 students

---

### Step 3: Frequency table

| Interval  | Frequency (number of students) |
|-----------|--------------------------------|
| (0, 20]   | 0                              |
| (20, 40]  | 0                              |
| (40, 60]  | 1                              |
| (60, 80]  | 3                              |
| (80, 100] | 4                              |

---

### Step 4: Histogram description

- 0 students scored between (0, 20]
- 0 students scored between (20, 40]
- 1 student scored between (40, 60]
- 3 students scored between (60, 80]
- 4 students scored between (80, 100]

---

This histogram shows most students scored above 60, with the highest number scoring between 80 and 100.

A histogram titled, Countries represented at each festival, plots Number of festivals, versus Number of countries, from 0 to 29, in increments of 5. Bar heights are approximately as follows. From 0 to 5, 1. From 6 to 11, 3. From 12 to 17, 5. From 18 to 23, 4. From 24 to 29, 2.\[0\]
\[1\]
\[2\]
\[3\]
\[4\]
\[5\]
\[6\]
\[0\text{-}5\]
\[6\text{-}11\]
\[12\text{-}17\]
\[18\text{-}23\]
\[24\text{-}29\]
How many festivals were there?
 festivals
Related content

Let's analyze the histogram to find the total number of festivals.

---

### Given data:

| Number of countries | Number of festivals (height of bar) |
|---------------------|-------------------------------------|
| 0–5                 | 1                                   |
| 6–11                | 3                                   |
| 12–17               | 5                                   |
| 18–23               | 4                                   |
| 24–29               | 2                                   |

---

### Step: Add up the number of festivals from each group to find the total:

\[
1 + 3 + 5 + 4 + 2 = 15
\]

---

### Answer:

There were **15 festivals** in total.

A histogram titled, Cherries in each cherry pie at Bernetta's Bakery, plots Number of pies, versus Number of cherries, from 0 to 149, in increments of 29. There is no bar between 0 and 29. Bar heights are approximately as follows. From 30 to 59, 5. From 60 to 89, 10. From 90 to 119, 4. From 120 to 149, 3.\[0\]
\[2\]
\[4\]
\[6\]
\[8\]
\[10\]
\[12\]
\[0\text{-}29\]
\[30\text{-}59\]
\[60\text{-}89\]
\[90\text{-}119\]
\[120\text{-}149\]
How many cherry pies have 
\[90\] or more cherries?
 pies
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Let's analyze the histogram data for cherry pies with **90 or more cherries**.

---

### Given data:

| Number of cherries | Number of pies (bar height) |
|--------------------|-----------------------------|
| 0–29               | 0                           |
| 30–59              | 5                           |
| 60–89              | 10                          |
| 90–119             | 4                           |
| 120–149            | 3                           |

---

### Step: Find total pies with 90 or more cherries

- Pies with 90–119 cherries: 4
- Pies with 120–149 cherries: 3

\[
4 + 3 = 7
\]

---

### Answer:

**7 pies** have 90 or more cherries.

A histogram titled, Distance driven for each vehicle at Nam's Gas Station, plots Number of vehicles, versus Distance, in thousands of kilometers, from 0 to 300, in increments of 50. Bar heights are approximately as follows. From 0 to 50, 3. From 50 to 100, 4. From 100 to 150, 5. From 150 to 200, 6. From 200 to 250, 3. From 250 to 300, 2.\[0\]
\[2\]
\[4\]
\[6\]
\[8\]
\[0\]
\[50\]
\[100\]
\[150\]
\[200\]
\[250\]
\[300\]
How many more vehicles have been driven between 
\[50\] and 
\[100\] thousand kilometers than between 
\[250\] and 
\[300\] thousand kilometers?
 vehicles
Related content

Let's analyze the histogram to find how many more vehicles were driven between 50 and 100 thousand kilometers compared to between 250 and 300 thousand kilometers.

---

### From the histogram:

- Vehicles driven between 50 and 100 thousand km: **4**
- Vehicles driven between 250 and 300 thousand km: **2**

---

### Calculate the difference:

\[
4 - 2 = 2
\]

---

### Answer:

**2 more vehicles** have been driven between 50 and 100 thousand kilometers than between 250 and 300 thousand kilometers.

Jerome runs a hostel where he offers budget-friendly housing in shared rooms to visiting guests. The following histogram shows the number of guests in each hostel room.
For this histogram, each bin includes the left endpoint and excludes the right endpoint.
A histogram titled, Guests in each hostel room, plots Number of hostel rooms, versus Number of guests, from 0 to 23, in increments of 3. Bar heights are approximately as follows. From 0 to 3, 3. From 4 to 7, 5. From 8 to 11, 8. From 12 to 15, 6. From 16 to 19, 2. From 20 to 23, 1.
\[0\]
\[2\]
\[4\]
\[6\]
\[8\]
\[10\]
\[0\]
\[4\]
\[8\]
\[12\]
\[16\]
\[20\]
\[24\]
How many hostel rooms have 
\[11\] or fewer guests?
 rooms
Related content
Report a problem

Let's analyze the histogram to find how many hostel rooms have **11 or fewer guests**.

---

### Given bins and frequencies (each bin **includes the left endpoint** and **excludes the right endpoint**):

| Bin (Number of guests) | Number of rooms (bar height) |
|------------------------|------------------------------|
| 0 to 3                 | 3                            |
| 4 to 7                 | 5                            |
| 8 to 11                | 8                            |
| 12 to 15               | 6                            |
| 16 to 19               | 2                            |
| 20 to 23               | 1                            |

---

### Step: Count rooms with **11 or fewer guests**

- Sum rooms in bins:  
  - 0 to 3 → 3  
  - 4 to 7 → 5  
  - 8 to 11 → 8  

\[
3 + 5 + 8 = 16
\]

---

### Answer:

**16 rooms** have 11 or fewer guests.

A histogram titled, Mass of each pumpkin in Leonard's patch, plots Number of pumpkins, versus Mass, in kilograms, from 0 to 15, in increments of 3. Bar heights are approximately as follows. From 0 to 3, 4. From 3 to 6, 5. From 6 to 9, 8. From 9 to 12, 6. From 12 to 15, 2.\[0\]
\[2\]
\[4\]
\[6\]
\[8\]
\[10\]
\[0\]
\[3\]
\[6\]
\[9\]
\[12\]
\[15\]
How many pumpkins are in Leonard's patch?
 pumpkins

Let's analyze the histogram to find the total number of pumpkins in Leonard's patch.

---

### Given bins and frequencies (mass in kilograms, bar heights):

| Mass range (kg) | Number of pumpkins |
|-----------------|--------------------|
| 0 to 3          | 4                  |
| 3 to 6          | 5                  |
| 6 to 9          | 8                  |
| 9 to 12         | 6                  |
| 12 to 15        | 2                  |

---

### Step: Add up all pumpkins:

\[
4 + 5 + 8 + 6 + 2 = 25
\]

---

### Answer:

There are **25 pumpkins** in Leonard's patch.

The data below shows the number of bags that each of the eight exchange students from Bridgewater University packed.
A table with 2 rows and 4 columns. On the top row from left to right are the numbers: 1, 4, 4, and 4. On the bottom row from left to right are the numbers 3, 2, 2, and 5.
Using this data, create a frequency table.
Number of bags	Number of exchange students
\[1\]	
\[2\]	
\[3\]	
\[4\]	
\[5\]	

Let's create the frequency table using the data given.

---

### Data (number of bags each student packed):
- Row 1: 1, 4, 4, 4
- Row 2: 3, 2, 2, 5

---

### Step 1: List the unique numbers of bags and count how many students packed that many bags:

| Number of bags | Count (Number of students) |
|----------------|----------------------------|
| 1              | 1 (from the first row)     |
| 2              | 2 (two students packed 2)  |
| 3              | 1                          |
| 4              | 3                          |
| 5              | 1                          |

---

### Final frequency table:

| Number of bags | Number of exchange students |
|----------------|-----------------------------|
| 1              | 1                           |
| 2              | 2                           |
| 3              | 1                           |
| 4              | 3                           |
| 5              | 1                           |